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V. Ivanchuk (2779) - P. Leko (2751) [E04]
Rapid Rematch/Mukachevo UKR (3) 2009
1. d4 Nf6 2. c4 e6 3. g3 d5 4. Bg2 dxc4 5. Nf3 c5 6.
14. Rfd1 c5 15. Be5 Ng4 16. e3 Nxe5 17. Nxe5
Schroeder-Klovans, Muenster 1994
14... c5 15. Qa4+ Nd7 16. b4!? g5! 16... cxb4 17. Rfc1
17. Nc6 Nb6 18. Qb5
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18... a6 18... Qd5!? 19. Nxd4+ (19. Nxe7+ Kxe7 20. e4! Qc4! 21. Bxg5+ f6 22. Qxc5+ Qxc5 23. bxc5 fxg5 24. cxb6 axb6
)
19... Kf8 20. bxc5 gxf4 21. cxb6 Qxb5 22. Nxb5 axb6
19. Qa5 Nc4 20. Qxd8+ Bxd8 21. Rac1 gxf4 22. Rxc4 cxb4 23. Rxb4 fxg3 24. hxg3 Bf6 25. Nxd4 Rc8
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26. Nf3
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P. Leko (2751) - V. Ivanchuk (2779) [B90]
Rapid Rematch/Mukachevo UKR (4) 2009
1. e4 c5 2. Nf3 d6 3. d4 cxd4 4. Nxd4 Nf6 5. Nc3 a6 6. Be3 e5 7. Nb3 Be6 8. f3 h5 9. Qd2 Nbd7 10. Nd5 Bxd5 10... Nxd5 11. exd5 Bf5 12. Be2 Be7 13.
Ivanchuk-Ljubojevic, Monte Carlo (rapid) 1998
11. exd5 g6 11... b6 12. Be2 g6 13.
12... Bg7 13. Qb4 Qc7 14. Na5
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13... Bh6 14. Bxh6 Rxh6 15. h4 Kf8 16. g3 Kg7 17. Kb1 Rh8 Black has equalized comfortably... 18. c4 Re8 19. Be2 Rc8 20. Rc1 e4 ...and now he grabs the initiative. 21. f4 e3 22. Rhg1 Ne4 23. Ka1 Nd7 24. Qxd8 Rcxd8 25. Na5 Ndc5
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26. Rc2 A long and difficult line to calculate, and to assess, is 26. b4 Na4 27. Nxb7 Rb8 28. Bd1 Nac3 29. Nxd6 Nxd6 30. Rxc3 e2 31. Bxe2 Rxe2 32. c5 Nb5 26... Rc8 27. b3 Rc7 28. Kb2 Rec8 29. Rcc1 Nd7 30. Bd3 Nf2 31. Be2 Nf6 32. Rge1 N6e4 33. Rg1 f5 34. Rc2 Kf6 35. Rcc1 Re7 36. Rc2 Rcc7 37. a3 Re8 38. Rg2
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38... Nh1! 39. Bf3 Nhxg3 39... Nexg3 looks strong too: 40. Rc1 e2 41. Bxe2 Rxe2+ 42. Rxe2 Nxe2 43. Rxh1 Nxf4
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40. Rg1 Nd2! 41. Rxg3 41. Rxd2 exd2 42. Rxg3 b6 43. Nc6 Re3! 44. Kc2 d1=Q+ 45. Kxd1 Rxb3 and Black is close to winning here as well.
41... Nxf3 42. Re2 Nxh4 43. b4 Re4 44. c5
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44... dxc5?! 44... Rd7 is probably better - Black might well be winning then. 45. d6! Rd7 46. bxc5 This is probably a draw already. 46... Rxf4 47. Rgxe3 Re4 48. Rxe4 fxe4 49. Rxe4 Nf5 50. Rb4 Nxd6 51. cxd6 Rxd6 52. Nxb7 Rd5 53. Kc3 Rb5 54. Kd3 Rxb4 55. axb4 h4 56. Ke3 h3 57. Kf2 Ke5 58. Nc5 Kd4 59. Nxa6 Kc4 60. Kg3 Kb5 61. Nc7+ Kxb4 62. Kxh3 1/2-1/2